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GagD!,J(K Fs,IqW.+QqJO*7kWbg.>H&\#,"39*"  y]IvAzq_% V=2ǎVq2A9GVNL\[e7l!S_eloq^_\7HA(Hw}ҕ4G[#쫇cj(ȳ{qo0)"%Gj)ձL^S*Jy[I(%LR*s&Y#kFd҂UڒߔNҋUHrE\UfkRb;\ϣ^krBmv+wRyTzg(;^IW{(PNJVKx\SIV>Gq[D)5p^}ZѼO)}K&7}WH$7vIx6ABdZd%?R5>gwmy"2ޑm}>Oj>!U۸V;,yCM#mԪ5!iF[3Q}tW~j-ZT#*dZz_jmr@ONE9N'jwOO@NXhS'k'i~CX}{GUj=QwT t+dG-:ަ孧VU xq QyRHOLu- 󈮎#m]$QRX-8rzA{6^~_]#PW#r&2YWmPԍq^-_U7=X͑{r>-4/Rd 꼉 GI'4^Dݯ 6#CԇS1&xǪOy'"؞>xD.-RqYknT-jY%iha>"O1>!?"?Y%sdړLQ{q?BF#c{(?jGsk `:sg$i}q~ύܧO'CH1ڐP6TnLa[n9v$O%/ ( F/ 0|DArial Ne(0(:A 0 DWingdings(0(:A 0  DTimes New Roman(0(:A 0 0DCourier Newman(0(:A 0 1@DSymbol Newman(0(:A 0  B .  @n?" dd@  @@`` X"  !         O2$;q\>5@{2$s􍭿1V h2$ȿ({bvUU702$ֲ y+``g 0AA 33fff@8q_L ʚ;b8ʚ;g4kdkd@:A 0ppp@  <4ddddl # 0v0___PPT10 6___PPT9{A0?\+ HAddress Register Indirect AddressingO =E The Pointer RegisterThis presentation demonstrates how a pointer register is used to implement address register indirect addressing. We look at an example where a sequence of consecutive elements in memory are accessed..ZK$ff[2Memory  address and dataA memory consists of a sequence of consecutive locations. Each location has a byte address. A single byte is stored in each location The notation [1234] = 25 means that the contents of memory location 1234 is the value 25.Instructions and NotationWe will assume a register-based three instruction format. The operation ADD R1,R2,R3 adds the contents of register R3 to register R2 and puts the result in register R1. All destination (result) operands will be in bold fond to improve readability. The notation #n in an instruction means the number n not the memory location n. The notation [R1] in an instruction means that R1 contains the address of the operand in memory.ZH$cMemory Structure  The ProblemWe want to add together the ten numbers in consecutive memory locations 100016 to 100916. A simple algorithm is: Sum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAdded rH+       >  Adding the Numbers The Pointer Register The Pointer Register Accessing Memory via a Pointer$Incrementing the PointerPointing to the Next Element The Algorithm in Machine Code$ The Algorithm in Machine Code$ The Algorithm in Machine Code$ The Algorithm in Machine Code$ The Algorithm in Machine Code$The Algorithm in Machine Code$The Algorithm in Machine Code$L  ` 33f` 333̙ffff` 2S___Xf___` =J3f̙` ]333̙Ԍ` 333fmff3m` 7"!ff` )))̙̙3>?" dd@(?nFd@ A0nF/1K#0nF$ n?" dd@   @@``PP  1 0 $` p>>  !T(  T T 0'd@,$ 0 <  T H)dd` <  T 6- =K  T Click to edit Master title style! ! T 0t/ V0  RClick to edit Master text styles Second level Third level Fourth level Fifth level!     S T 006 `T  X*  T 0: `@`   Z*  T 0? `0  Z*   T n@ABCDEF)@#" bp  T n@ABCDEF)@#" UNH T 0޽h ? )))̙̙380___PPT10. ,> Axis      X(  X X 0  <$ 0  W#Click to edit Master subtitle style$ $ X 0 ``  X*  X 0 `   Z*   X 0x `   Z* X @`p  XC @ABC@`p2 X <1@p <  X 6\    <  X Nd  ` <   X n@ABCDEF)@#" Q  X n@ABCDEF)@#" PZ X 6 }  T Click to edit Master title style! !H X 0޽h ? )))̙̙380___PPT10. ,> 0 zr0 (    0@ P    P*    0     R*  d  c $?    0  0  RClick to edit Master text styles Second level Third level Fourth level Fifth level!     S  6 _P   P*    6( _   R*  H  0޽h ? 3380___PPT10.Hp} @$(  r  S 8X}  r  S 9X   H  0޽h ? 33___PPT10i.Ga+D=' = @B +}  P$(  r  S {T=K   r  S |TV0  H  0޽h ? 33___PPT10i.P0X+D=' = @B +}  `T$(  Tr T S oT=K   r T S pTV0  H T 0޽h ? 33___PPT10i.P0X+D=' = @B +7    p p (  r  S \T=K   @   ADE&VfX TBasic1  `  `T`T  `T `T`T `TPp    6젎0  > 2 l 0 0,$D  0HB   C 0    <  NAddress 100016$ 2  l 0 T  0 T ,$D  0HB  C 0   < T  u+Address 100416. Each location holds a byte.., 2   l @  @ ,$D  0Z2  s *G@ 0 BB  3 0 P   6x  w-The contents of memory location 100716 is 76... 2$ b  6Lp ,$@  0 lWe can use a formal notation and write [100716 ] = 76 To indicate that the contents of location 1007 are 76.@m 2,?H  0޽h ? 33--___PPT10k-.H +_HD?-' =*@B BTimeNode0D,' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<*%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D' =BTimeNode12%(D' =BTimeNode13%(D0' =SBTimeNode14BBB@B%(D,' =BTimeNode15+4 8?XCB ppt_xBCB ppt_xB*Y3>B ppt_x<*D4' =BTimeNode16+4 8?`CB ppt_yBCB1+ppt_h/2B*Y3>B ppt_y<*D' =BTimeNode171:Bhidden*o3>+B#style.visibility<*%(D(' =BTimeNode22%(D' =BTimeNode23%(D:' =SBTimeNode24BBB@B%(D' =BTimeNode251:Bvisible*o3>+B#style.visibility<*%(D8' =BTimeNode26+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D0' =BTimeNode27+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D' =BTimeNode32%(D' =BTimeNode33%(D0' =SBTimeNode34BBB@B%(D,' =BTimeNode35+4 8?XCB ppt_xBCB ppt_xB*Y3>B ppt_x<*D4' =BTimeNode36+4 8?`CB ppt_yBCB1+ppt_h/2B*Y3>B ppt_y<*D' =BTimeNode371:Bhidden*o3>+B#style.visibility<*%(D(' =BTimeNode42%(D' =BTimeNode43%(D:' =SBTimeNode44BBB@B%(D' =BTimeNode451:Bvisible*o3>+B#style.visibility<*%(D8' =BTimeNode46+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D0' =BTimeNode47+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D' =BTimeNode52%(D' =BTimeNode53%(D0' =SBTimeNode54BBB@B%(D,' =BTimeNode55+4 8?XCB ppt_xBCB ppt_xB*Y3>B ppt_x<*D4' =BTimeNode56+4 8?`CB ppt_yBCB1+ppt_h/2B*Y3>B ppt_y<*D' =BTimeNode571:Bhidden*o3>+B#style.visibility<*%(D ' =BTimeNode62%(D' =BTimeNode63%(D' =SBTimeNode64BBB@B%(D' =BTimeNode651:Bvisible*o3>+B#style.visibility<*'%(D' =BTimeNode66-m6Bbox(in)*<3<*'D' =SBTimeNode67BBB@B%(D' =BTimeNode681:Bvisible*o3>+B#style.visibility<*'6%(D' =BTimeNode69-m6Bbox(in)*<3<*'6D1' =4BBB@B%(D' =1:Bvisible*o3>+B#style.visibility<*6m%(D' =-m6Bbox(in)*<3<*6mD' =BTimeNode70%(Dw' =SBTimeNode71BBB@B%(D' =BTimeNode72/u8CC*Q3> Br<*'Dw' =SBTimeNode73BBB@B%(D' =BTimeNode74/u8CC*Q3> Br<*'6D9' =4BBB@B%(D' =/u8CC*Q3> Br<*6m+   (  r  S \ÎT=K   r  S 0ĎTV0  l p   p ,$D  0Z2  s *h ` P BB  3 `   6xƎ p  {GWe will use the subscript 1000 to indicate the number at location 1000.H 2HZl p   p ,$D  0`2   0hp 0 HB   C   &   <@̎  ~The subscript  next indicates the next number in the sequence.@ 2@H  0޽h ? 33___PPT10l.cP~+oD@' =*@B BTimeNode0D' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<* %(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* D' =BTimeNode12%(D-' =BTimeNode13%(D' =SBTimeNode14B BB@B%()))D' =BTimeNode15-g6B fade*<3<* D' =BTimeNode161:Bhidden*o3>+B#style.visibility<* %(D(' =BTimeNode20%(D' =BTimeNode21%(D:' =SBTimeNode22BBB@B%(D' =BTimeNode231:Bvisible*o3>+B#style.visibility<*%(D8' =BTimeNode24+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D0' =BTimeNode25+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*+y8  D< 0  (  r  S T=K   @   ADE&VfX TBasic1  `  `T`T  `T `T`T `T6 Q  6Ř GSum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAddedBH    >! ?l 0` 0`,$D  0Z2  s *E0BB   3    6\˜0` -Step 1 Get number at location 100016. Sum = 4`. 2 3 3 3 3 3Rl 0`J  0`J ,$D  0`2  0E0HB  C     <Ϙ`J  .Step 2 Add number at location 100116. Sum = 60`/ 2 3 3 3 3  3Sl 0P`  P0` ,$D  0`2  0E0P@HB  C `   <p `  /Step 3 Add number at location 100216. Sum = 106`0 2 3 3 3 3  3Sl 0`Z 0`Z,$D  0`2  0E0 HB  C   <|ܘ `Z /Step 4 Add number at location 100316. Sum = 138`0 2 3 3 3 3  3   6  :,$   0 |:This sequence continues until all numbers have been added.&; 29ffH  0޽h ? 33))___PPT10).ep^+.DQ)' =*@B BTimeNode0D(' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<*%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D' =BTimeNode12%(D-' =BTimeNode13%(D' =SBTimeNode14B BB@B%()))D' =BTimeNode15-g6B fade*<3<*D' =BTimeNode161:Bhidden*o3>+B#style.visibility<*%(D(' =BTimeNode20%(D' =BTimeNode21%(D:' =SBTimeNode22BBB@B%(D' =BTimeNode231:Bvisible*o3>+B#style.visibility<*%(D8' =BTimeNode24+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D0' =BTimeNode25+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*Dt' =BTimeNode30%(D' =BTimeNode31%(D' =SBTimeNode32B BB@B%(D' =BTimeNode33-g6B fade*<3<*D' =BTimeNode341:Bhidden*o3>+B#style.visibility<*%(D(' =BTimeNode38%(D' =BTimeNode39%(D:' =SBTimeNode40BBB@B%(D' =BTimeNode411:Bvisible*o3>+B#style.visibility<*%(D8' =BTimeNode42+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D0' =BTimeNode43+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*Dt' =BTimeNode48%(D' =BTimeNode49%(D' =SBTimeNode50B BB@B%(D' =BTimeNode51-g6B fade*<3<*D' =BTimeNode521:Bhidden*o3>+B#style.visibility<*%(D(' =BTimeNode56%(D' =BTimeNode57%(D:' =SBTimeNode58BBB@B%(D' =BTimeNode591:Bvisible*o3>+B#style.visibility<*%(D8' =BTimeNode60+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D0' =BTimeNode61+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*Dt' =BTimeNode66%(D' =BTimeNode67%(D' =SBTimeNode68B BB@B%(D' =BTimeNode69-g6B fade*<3<*D' =BTimeNode701:Bhidden*o3>+B#style.visibility<*%(D5' =BTimeNode74%(D' =BTimeNode75%(DG' =`BTimeNode76BBB@B0B%(D' =BTimeNode771:Bvisible*o3>+B#style.visibility<* %(D8' =BTimeNode78+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D0' =BTimeNode79+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* +8+0+  +h   h(  r  S 0ގT=K      6xߎ `:  PThe next step is to introduce the pointer register. A register holds a variable. A pointer register holds a variable that is the address of a variable in memory. When you access data via a pointer register, you access the data being pointed at by the register.0 2j6ffeH  0޽h ? 3380___PPT10.l'  Xz(  Xr X S T=K   @ X  ADE&VfX TBasic2  `  `T`T  `T `T`T `Tl   X 6 ,$  0 Register R1 contains the value 100016. The number in R1 is the address of the first number in the list. Register R1 is said to point at the location it contains.. 2#  }  X 6p ` ,$  0 Y%Register R1 points at the element 04.& 2& H X 0޽h ? 33r j ___PPT10J .l'+ D ' =*@B BTimeNode0DL ' =*BTimeNode1@BA?%,( < +O%,( < +D)' =BTimeNode2%(D' =BTimeNode3%(D?' =^BTimeNode4BBB@B0B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<*X%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*XD.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*XD5' =BTimeNode12%(D' =BTimeNode13%(DG' =`BTimeNode14BBB@B0B%(D' =BTimeNode151:Bvisible*o3>+B#style.visibility<*X%(D8' =BTimeNode16+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*XD0' =BTimeNode17+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*X+p+0+X ++0+X +  ,G(  ,r , S T=K   @ ,  ADE&VfX TBasic2  `  `T`T  `T `T`T `T< -   , 6 ,$  0 A typical memory register indirect memory access is written LOAD R2,[R1] This means load register R2 with the contents of the memory location whose address is in R1.H 2<] , 64   ,$  0 We can represent this action in register transfer language as [R2] [[R1]]VL 2>H , 0޽h ? 33r j ___PPT10J .l'+WD ' =*@B BTimeNode0DL ' =*BTimeNode1@BA?%,( < +O%,( < +D)' =BTimeNode2%(D' =BTimeNode3%(D?' =^BTimeNode4BBB@B0B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<*,%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,D5' =BTimeNode12%(D' =BTimeNode13%(DG' =`BTimeNode14BBB@B0B%(D' =BTimeNode151:Bvisible*o3>+B#style.visibility<*,%(D8' =BTimeNode16+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D0' =BTimeNode17+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,+p+0+, ++0+, +   u(  r  S  ,T=K   @   ADE&VfX TBasic3  `  `T`T  `T `T`T `T 8 R  6@" ,$  0 ^Suppose we add 1 to the contents of the pointer register with an instruction like ADD R1,R1,#1>_ 2R!   6S @p ,$  0 =After the addition, the pointer register now contains 100116..> 2: H  0޽h ? 33___PPT10.wC+D' =*@B BTimeNode0D' =*BTimeNode1@BA?%,( < +O%,( < +D)' =BTimeNode2%(D' =BTimeNode3%(D?' =^BTimeNode4BBB@B0B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<*%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D+' =BTimeNode12%(D' =BTimeNode13%(D=' =`BTimeNode14BBB@B0B%(D,' =BTimeNode15+4 8?XCB ppt_xBCB ppt_xB*Y3>B ppt_x<*D4' =BTimeNode16+4 8?`CB ppt_yBCB1+ppt_h/2B*Y3>B ppt_y<*D' =BTimeNode171:Bhidden*o3>+B#style.visibility<*%(D5' =BTimeNode22%(D' =BTimeNode23%(DG' =`BTimeNode24BBB@B0B%(D' =BTimeNode251:Bvisible*o3>+B#style.visibility<* %(D8' =BTimeNode26+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D0' =BTimeNode27+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* ++0+S ++0+S ++0+ S +   (   r   S ST=K  S @    ADE&VfX TBasic4  `  `T`T  `T `T`T `T  w S1   6SPp ,$  0 cBecause we added 1 to the pointer, register R1 is now pointing at the next element in the sequence.d 2d[   6S p,$  0 wBecause we added 1 to the pointer, register R1 contains 100116 and is now pointing at the next element in the sequence..x 2< :H   0޽h ? 33r j ___PPT10J .w0\Z+{]D ' =*@B BTimeNode0DL ' =*BTimeNode1@BA?%,( < +O%,( < +D)' =BTimeNode2%(D' =BTimeNode3%(D?' =^BTimeNode4BBB@B0B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<* %(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* D5' =BTimeNode12%(D' =BTimeNode13%(DG' =`BTimeNode14BBB@B0B%(D' =BTimeNode151:Bvisible*o3>+B#style.visibility<* %(D8' =BTimeNode16+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D0' =BTimeNode17+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* +p+0+ S ++0+ S +  0(  0r 0 S ST=K  S [ 0 6 SpP  GSum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAddedLH    >! y 0 6`S0 P e LOAD R1,#100016 Register R1 points to the numbers LOAD R2,[R1] Register R2 holds the first number Repeat ADD R1,R1,#1 Register R1 points to the next number ADD R2,R2,[R1] Add the number pointed at by R1 to the sum CMP R1,#100916 Are we at the last memory location? BNE Repeat If not last number then repeat. f 2  " # &  + & " H 0 0޽h ? 3380___PPT10.|ST  D <  <(  <r < S ST=K  S [ < 6DSpP  GSum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAddedLH    >!  < 6 0 P d LOAD R1,#100016 Register R1 points to the numbers LOAD R2,[R1] Register R2 holds the first number Repeat ADD R1,R1,#1 Register R1 points to the next number ADD R2,R2,[R1] Add the number pointed at by R1 to the sum CMP R1,#100916 Are we at the last memory location? BNE Repeat If not last number then repeat. e 2  " # &+ #   < 6lB0 > 2 %l    < ,$D  0Z2 < s *33 BB <B 3  `  < 6DE WInitialize the pointer by loading it with the address of the first number in the table.X 2X3H < 0޽h ? 33___PPT10.|S+"Dd' =*@B BTimeNode0D' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<* <%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* <D.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* <+   y  @ (  @r @ S XOT=K   [ @ 6SpP  GSum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAddedLH    >!  @ 6U0 P d LOAD R1,#100016 Register R1 points to the numbers LOAD R2,[R1] Register R2 holds the first number Repeat ADD R1,R1,#1 Register R1 points to the next number ADD R2,R2,[R1] Add the number pointed at by R1 to the sum CMP R1,#100916 Are we at the last memory location? BNE Repeat If not last number then repeat. e 2 " # &+ #   @ 6X0 > 2 Nl `   @` ,$D  0`2 @ 033`  HB @B C    @ <[ PRead the first element by loading register R2 with the element pointed at by R1.:Q 23333H @ 0޽h ? 33___PPT10.|S+HFDd' =*@B BTimeNode0D' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<* @%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* @D.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* @+     DD (  Dr D S gT=K   [ D 6pP  GSum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAddedLH    >!  D 6T0 P d LOAD R1,#100016 Register R1 points to the numbers LOAD R2,[R1] Register R2 holds the first number Repeat ADD R1,R1,#1 Register R1 points to the next number ADD R2,R2,[R1] Add the number pointed at by R1 to the sum CMP R1,#100916 Are we at the last memory location? BNE Repeat If not last number then repeat. e 2 "#&+#   D 60 > 2 kl `   D` ,$D  0Z2 D s *33`  BB DB 3  C D 6l We now have to update the pointer. This operation adds 1 to the contents of the pointer register which moves the pointer to the next element in the sequence. 23H D 0޽h ? 33___PPT10.|S+"Dd' =*@B BTimeNode0D' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<* D%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* DD.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* D+    0 HU (  Hr H S T=K   [ H 6pP  GSum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAddedLH    >!  H 6 0 P d LOAD R1,#100016 Register R1 points to the numbers LOAD R2,[R1] Register R2 holds the first number Repeat ADD R1,R1,#1 Register R1 points to the next number ADD R2,R2,[R1] Add the number pointed at by R1 to the sum CMP R1,#100916 Are we at the last memory location? BNE Repeat If not last number then repeat. e 2 "# &+#   H 60 > 2 |l `   H` ,$D  0`2 H 033`  HB HB C  H H <pd Add the next number to the running total in R2. The operand in memory is specified by [R1] which means the contents of the memory location pointed at by R1. 23H H 0޽h ? 33___PPT10.|S+HFDd' =*@B BTimeNode0D' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<* H%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* HD.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* H+(    @ L(  Lr L S T=K   [ L 6SpP  GSum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAddedLH    >! x L 60 P d LOAD R1,#100016 Register R1 points to the numbers LOAD R2,[R1] Register R2 holds the first number Repeat ADD R1,R1,#1 Register R1 points to the next number ADD R2,,R2[R1] Add the number pointed at by R1 to the sum CMP R1,#100916 Are we at the last memory location? BNE Repeat If not last number then repeat. e 2" #&+  &   L 60 > 2 gl    L ,$D  0Z2 L s *33 BB LB 3  ? L 6 {Have we reached the end of the list yet? The address of the last item is 100916, so we compare the pointer with this value.:| 2M33-3H L 0޽h ? 33___PPT10.|S+"Dd' =*@B BTimeNode0D' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<* L%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* LD.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* L+    P P (  Pr P S T=K   [ P 6FpP  GSum = Number1000 Repeat Sum = Sum + Numbernext Until allNumbersAddedLH    >!  P 6L0 P d LOAD R1,#100016 Register R1 points to the numbers LOAD R2,[R1] Register R2 holds the first number Repeat ADD R1,R1,#1 Register R1 points to the next number ADD R2,R2,[R1] Add the number pointed at by R1 to the sum CMP R1,#100916 Are we at the last memory location? BNE Repeat If not last number then repeat.  e 2 "# &+ # "  P 6S0 > 2 Tl 0  P0,$D  0Z2 P s *330 BB PB 3 p , P 6Vx hIf the pointer is not pointing at the last element at address 100916, then go and add in the next number:i 2B33%3H P 0޽h ? 33___PPT10.|S+"Dd' =*@B BTimeNode0D' =*BTimeNode1@BA?%,( < +O%,( < +D' =BTimeNode2%(D' =BTimeNode3%(D2' =QBTimeNode4BBB@B%(D' =BTimeNode51:Bvisible*o3>+B#style.visibility<* P%(D6' =BTimeNode6+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* PD.' =BTimeNode7+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* P+r\`-h#35%8:rIZ(O9J[4km{;Oh+'0@ hp    (The Pointer RegisterPAlan ClementsgiAxisCleAlan Clementsgi58nMicrosoft PowerPointP@1@zG@ }Gg    -- @ !--'@Arial-. ))) 2 |18."Systemti-@Arial-. ))) 2 |- .-@Arial-. ))) 2 |Nov .-@Arial-. ))) 2 |- .-@Arial-. ))) 2 | 03.-@Arial-. )))=2 |$Address Register Indirect Addressing    .-@Arial-. ))) 2 |1.-̙--%E6( y"p,h6`AYLSWMcGoB|>:753222357:>,B9GFMRS^Yi`thpy (6ESan|!)t0i6^<RBFG9K,ORTVWXWVTROKG|Bo<c6W0L)A!6,"|naSE--'̙-- @ ! n--'-̙-- @ !'nb--͛-- @ !,n--͝-- @ ! n--Ο-- @ !n--ϡ-- @ !n--У-- @ !n --ѥ-- @ !n--ҧ-- @ !n2--ө-- @ !nF--ԫ-- @ !nV--ԭ-- @ !ng--կ-- @ !nw--ֱ-- @ ! n--׳-- @ !n--ص-- @ !n--ٷ-- @ ! n--ڹ-- @ ! n--ۻ-- @ ! n--ܽ-- @ ! n--ݿ-- @ !n---- @ !n---- @ !n---- @ ! n ---- @ ! n---- @ ! n$---- @ ! n0---- @ ! n<---- @ ! nI---- @ ! nU---- @ ! na---- @ ! nm---- @ ! ny---- @ !n---- @ ! n---- @ ! n---- @ !n---- @ !n---- @ ! n---- @ !n---- @ !n---- @ !n---- @ !n ---- @ !n---- @ !n3---- @ !nG---- @ !n[---- @ !ns---- @ ! n---- @ !(n---- @ !-n---- @ !$n---- @ !Bn)---'-- %MM--'̙-- %44--'@Arial-. %2 The Pointer RegisterE=>J>>>%P>>8>$.-@Arial-. )))K2 J-This presentation demonstrates how a pointer #  /' .-@Arial-. )))42 register is used to implement    / /.-@Arial-. ff!2 address register t .-@Arial-. ff$2 indirect addressingr   .-@Arial-. ))) 2 . .-@Arial-. )))F2 U*We look at an example where a sequence of 6 / '.-@Arial-. )))I2 ,consecutive elements in memory are accessed.  / //.-՜.+,D՜.+,    vOn-screen Shown-s*{ Arial WingdingsTimes New Roman Courier NewSymbolAxisThe Pointer RegisterMemory address and dataInstructions and NotationMemory Structure The ProblemAdding the NumbersThe Pointer RegisterThe Pointer RegisterAccessing Memory via a PointerIncrementing the PointerPointing to the Next ElementThe Algorithm in Machine CodeThe Algorithm in Machine CodeThe Algorithm in Machine CodeThe Algorithm in Machine CodeThe Algorithm in Machine CodeThe Algorithm in Machine CodeThe Algorithm in Machine Code  Fonts UsedDesign Template Slide TitlesD 4<Version%_?| Alan ClementsAlan Clements  !"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~      !"#$%&'()*+,-./013456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~    Root EntrydO)PicturescCurrent User SummaryInformation(p PowerPoint Document(2c|DocumentSummaryInformation8